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Relationship between Potential and Field

E = -∇V, where E is the electric field and V is the electric potential.
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The statement of the theorem

In the domain ΩR3\Omega \subset \mathbb{R}^3, let V(r)V(\vec{r}) be a scalar potential field, V:ΩRV: \Omega \to \mathbb{R}, and let E(r)\vec{E}(\vec{r}) be the associated electric field vector field. The relationship is defined by the negative gradient operation, which quantifies the rate of change of the potential in the direction of steepest descent (the direction of the field). Formally, the electric field E\vec{E} is the negative gradient of the electric potential VV: \n\nE=V\vec{E} = -\nabla V \n\nIn Cartesian coordinates, this relationship expands to:\n\nE=(Vxi^+Vyj^+Vzk^)\vec{E} = -\left( \frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j} + \frac{\partial V}{\partial z} \hat{k} \right) \n\nThis implies that the field E\vec{E} is a conservative vector field, satisfying the condition ×E=0\nabla \times \vec{E} = 0, which is a direct consequence of VV being a scalar potential function.
Source: Wikipedia