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Moments of Force

The turning effect of a force about a point, calculated as force multiplied by the perpendicular distance: \vec{M} = \vec{r} \times \vec{F}.
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The statement of the theorem

Let R3\mathbb{R}^3 be the Euclidean space equipped with a standard orthonormal basis {i^,j^,k^}\{\hat{i}, \hat{j}, \hat{k}\} and the dot product AB\vec{A} \cdot \vec{B} and cross product A×B\vec{A} \times \vec{B}. Consider a force F\vec{F} applied at a point PP relative to an origin O\vec{O}. The position vector r\vec{r} is defined as r=PO\vec{r} = \vec{P} - \vec{O}. The moment of force M\vec{M} about the origin O\vec{O} is defined by the vector cross product: M=r×F\vec{M} = \vec{r} \times \vec{F}. In Cartesian coordinates, if r=rx,ry,rz\vec{r} = \langle r_x, r_y, r_z \rangle and F=Fx,Fy,Fz\vec{F} = \langle F_x, F_y, F_z \rangle, the moment vector M=Mx,My,Mz\vec{M} = \langle M_x, M_y, M_z \rangle is given by the determinant expansion: M=i^j^k^rxryrzFxFyFz\vec{M} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ r_x & r_y & r_z \\ F_x & F_y & F_z \end{vmatrix} M=(ryFzrzFy)i^+(rzFxrxFz)j^+(rxFyryFx)k^\vec{M} = (r_y F_z - r_z F_y) \hat{i} + (r_z F_x - r_x F_z) \hat{j} + (r_x F_y - r_y F_x) \hat{k}. The magnitude of the moment is M=rFsin(θ)M = |\vec{r}| |\vec{F}| \sin(\theta), where θ\theta is the angle between r\vec{r} and F\vec{F}. Alternatively, M=Mx2+My2+Mz2M = \sqrt{M_x^2 + M_y^2 + M_z^2}. This quantity represents the rotational tendency (torque) of F\vec{F} about $\vec{O}.
Source: Wikipedia